解:原式=-4x²y³-2(xy-2y³x²+3x)+2xy
=2x(y - 2xy³ - y+ 2y³x - 3)
=-6x。
当x=10分之1,y=0.02105时,
原式=-6×﹙1/10﹚=﹣0.6.
(七岁腊改年局迟级问题,标准格式)
1.已知a²-ab=8 ab-b²=-4,则a²-b²=__4____,a²-2ab+b²=___-12___。
2.若多项乎判式3x²-2xy+y²+kxy+x+1不含xy,则k=___2___。
先化搜春或简:
-4x²y³-2(xy-2y³森锋x²+3x)+2xy
=2x(y - 2xy³ - y+ 2y³x - 3)
=-6x
然后世伍带入
原式=
-6 * 0.1 = -0.6
-4x²y³-2(xy-2y³搜野友x²世槐+3x)+2xy
=2x(y - 2xy³ - y+ 2y³脊培x - 3)
=-6x
=-6 * 0.1 = -0.6
解“:
-4x^2y^3-2(xy-2y^3x^2+3x)+2xy
=-4x²y³敬旦罩迟档-2xy+4x²y³-6x+2xy
=-6x
=-6×1/亮闹10
=-3/5
原漏陵唯式=-4x^2y^3-2xy 4y^3x^2-6x 2xy
=-6x
=-6×0.1
=-0.6
希望能返培对你汪扒有帮助
-4x²y³陆凯弊嫌-2(xy-2y³x²+3x)+2xy
=-4x²y³-2xy+4x²y³-6x+2xy
=-6x
因为x=0.1,早卜唤
所以-6x=-0.6