1)∠AOD=∠AOB+∠BOD=70°+50°=120°∠EOF=∠COE+∠凳郑银COF=∠AOC/2+∠BOC/2 =∠AOC/2+(∠AOB-∠AOC)/2 =50°/2+(70°-50°)/枣宴2 =25°+10 ° =35°2)∠FOG=∠BOF+∠BOG=∠BOC/2+∠BOD/2=20°/2+50°/2=35°因为:∠EOF=∠FOG所以:OF是丛晌∠EOG的平分线