由题意,有:1<=a2<=q<=a2+1<=q*q<=a2+2<=q*q*q,可知,当a2=1时,q取到极值,带入进去可以得到:q>=1,q<=2,q>=根号2,q<=根号3,q>=三次根号3.将上述结果求交集,即可得到q的取值范围q>=三次根号3
三次根号3