开念隐方:x^2-2x+1+y^2+4y+4=4
x^2+2x+1+y^2+8y+16=4
两式相减得:简睁-4x-4y-12=0
化简变形得:x=-y-3代入开放后的任一条式子
如代拦高岁入第一条得:(-y-3)^2-2(-y-3)+4y=4
解上式得:y=-11或-1,x=8或-2
求什么?
计:X-1=M,Y+2=N,有晌启M^2+N^2=4,(M+2)^2+(N+2)^2=20.化简有M+N=4,M^2+N^2=4.得悄粗当启谨镇M=0,X=1,N=2,Y=0;M=2,X=3,Y=-2.