解答:
设z=x+yi, x,y是实数
∴ (x+yi)(x-yi)+(1-2i)(x+yi)+(1+2i)(x-yi)=3
∴ x²+y²+(x+2y)+(y-2x)i+(x+2y)+(2x-y)i=3
∴ x²+y²+2x+4y=3
即 (x+1)²袭顷+(y+2)²=8
∴ z=x+yi对应点Z(x,y)在以M(-1,-2)为圆心,档歼2√2为半径的圆上拍蠢陆
|z+3i-4|的几何意义是Z到N(4,-3)的距离
|MN|=√[(-1-4)²+(-2+3)²]=√26
利用平面几何知识,
∴ |z+3i-4|的取值范围是[√26-2√2,√26+2√2]