䀧！急急急~一道初三化学题！望高手来解答！要详细啊！

(1)溶质质量=溶液物埋质量*溶质质量分数。本题凳漏：100g*8.64%=8.64g
体积=质量/密度,即 8.64g/1.20g/cm3=7.2cm3=7.2mL
(2)解：设理枣蚂烂论上可制得氢气的质量为x
Zn+2HCl=ZnCl2+H2↑
65 2
6.5g x
65/6.5g=2/x
x=0.2g

100*8.64%=X*1.2*36%
Zn+2HCl=ZnCl2+H2
65 2

6.5 y
y=0.2

(1)100g*8.64%=8.64g 体积：8.64g/1.20g/cm3=7.2cm3=7.2mL
(2)解蚂森：设理蔽物亮论上可宏宽制得氢气的质量为x
Zn+2HCl=ZnCl2+H2↑
65 2
6.5g x
65/6.5g=2/x
x=0.2g