f(x)=2+根号2*sin(x+p/4)(p 表示派)最大值为2加根号2;嫌桐携芹伏最小值为2减根号2;递减区间为{-3p/8+kp<轮岁=x<=p/8+kp}
化基唯简得f(x)=2+根号(2)*sin(2x+派/4) 所以最搏斗培大2+根号2最小2-根号2 区间(k派+派/8,k派+5派/8) 不好意思有些符销汪号手机打不出啊.不过应该可以看懂
f(x)
=sinx^2+cosx^2+2sinxcosx+2cos平方郑高x
=1+cos平袭丛源方x+2sinxcosx
=cos2x+2+sin2x
=根拍态号2*sin(2x+π/4)+2
max(根号2+2) min(2-根号2)
区间是 2x+π/4∈(π/2+2kπ,π3/2+2kπ) x∈(π/8+kπ,5π/8+kπ)
f(x)=1+2sinxcosx+2cos平方x
=sin(2x)+cos(2x)+2
=√2sin(2x+π/4)+2
f(x)的最族粗小值为2-√2,最大兆念镇值高运为2+√2
2kπ+π/2<2x+π/4<2kπ+3π/2
kπ+π/8
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这道题的详肢码解岩饥埋这里有,你可以粗蚂看看这题,一摸一样的