设AB=3X,则AC=5X,AF=3X,AD=3X+(3/2)X=(9/2)X,则CD=AD+AC=(19/2)X,
那么可得DE=(1/2)DC=(19/4)X>AD,可则E点在A点的右侧歼坦,
则AE=DE-AD=(1/4)X=2cm,
由悉胡此可得X=8cm,那氏陆桐么AB=3X=24cm
设AB=3X,则DA=3/2*3X=(9/2)X=4.5X,BC=2/3*3X=2X
所以DC=DA+AB+BC
=(9/2)X+3X+2X
=9.5X
DE=0.5*DC=4.75X>DA,则E点在A点右尘旁侧,派顷橡乎世
DE-DA=2
解:4.75X-4.5X=2
X=8
AB=3X=3*8=24cm