abc=1
所以
b=1/ac
ab=1/c
bc=1/a
所以原式=a/(1/c+a+1)+(1/ac)/(1/a+1/ac+1)+c/(ac+c+1)
第一个式子分子分母同乘以c
第慎碧二个兄悔式子分子分母同乘以ac
=ac/(ac+c+1)+1/宽尘举(ac+c+1)+c/(ac+c+1)
=(ac+c+1)/(ac+c+1)
=1
设abc等于1,求a/ab+a+1 + b/bc+b+1 +
c/ac+c+1
解:a/老激ab+a+1 + b/bc+b+1 + c/ac+c+1
=a/ab+a+abc + b/bc+b+1 + c/(1/b)+c+1
=1/扰链bc+b+1 + b/缓含孙bc+b+1 + bc/bc+b+1
=(1+b+bc)/(1+b+bc)
=1