证明△ABE相握漏李似△CBA∠ABE=∠CBAAB=BD=CD=(1/2)BCBE=(1/2)BD==(1/2)BA所以△ABE相似搜升△CBAAE=(1/段迟2)ACAC=2AE
AC=2AE
证明:∵∠宴前ABE=∠CBA∴早皮AB=BD=CD=(1/2)BC∴BE=(1/2)BD==(1/2)BA因此△ABE∽△CBA∴AE=(1/2)AC即陆祥差 AC=2AE