解:伏渣 2n-1 (n=2^(k-1)+k-1,k∈N+)bn= 2 (n≠2^(k-1)+k-1,k∈N+)Tn=2^k+k^2-2 (n=2^(k-1)+k-1,缺改悄k∈N+)2^k+k^2-2 ≤20102^k+k^2-2>2010得k=10Tn=T(2^(k-1)+k-1)=T(521)=2^k+k^2-2=1122(2010-1122)/歼模2=439m=521+439=960